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Relative formula mass (Mr)

AQA GCSE Chemistry calculation · part of the free Calculation Climb

The relative formula mass (Mr) is the mass of a whole formula — you get it by adding up the Ar of every atom in it. It's the closest thing GCSE Chemistry has to a free two marks, it comes up nearly every year, and it's also the opening step of half the harder calculations (moles, reacting masses, percentage by mass, percentage yield).

How to do it — step by step

  1. Count how many of each atom are in the formula — the little subscript number applies to the atom just before it.
  2. Multiply each atom's Ar by how many there are.
  3. Add it all up — never multiply the Ar values together. No units.
  4. Show the substitution line ("56 × 2 + 16 × 3") — it's a mark on its own, and it protects you if the arithmetic slips.

Worked examples — from real AQA papers

The standard two-marker. Calculate the Mr of Fe₂O₃. Ar: O = 16, Fe = 56.
(2 × 56) + (3 × 16) = 112 + 48 = 160
Three-fifths of students got both marks. The report lists what went wrong for the rest: "56 × 112 was frequently seen", and some read the subscripts backwards — three Fe and two O. The subscript belongs to the atom before it.
AQA GCSE Chemistry Paper 1, Foundation, 2023 — 2 marks
Watch the subscripts. Calculate the Mr of carbonic acid, H₂CO₃. Ar: H = 1, C = 12, O = 16.
(1 × 2) + 12 + (16 × 3) = 62
The most common wrong answer was 86 — from assuming the 3 applied to the carbon as well as the oxygen. Others simply added 1 + 12 + 16, ignoring the subscripts entirely, or multiplied the values together.
AQA GCSE Chemistry Paper 1, Foundation, 2022 — 2 marks
Mr in reverse. An amino acid H₂N–[section]–COOH has Mr = 75. Calculate the relative formula mass of the [section] part. Ar: H = 1, C = 12, N = 14, O = 16.
Mr of H₂N + COOH = (2×1) + 14 + 12 + (2×16) + 1 = 61 → section = 75 − 61 = 14
Around three-quarters of students got both marks; the common error was subtracting the two groups from each other rather than from 75. AQA also runs this trick with equations — e.g. "3H₂ + RO₃ has total Mr 150, find Ar of R" (answer: 96).
AQA GCSE Chemistry Paper 2, Higher, 2023 — 2 marks

Where students lose marks — from the examiner reports

How often it comes up on AQA papers

From Science Street's database of real AQA questions:

PaperMarksWhat you had to do
Chemistry Paper 1 Foundation 20202Mr of FeBr₃ → 296
Chemistry Paper 1 Foundation 20212Reverse: 3H₂ + RO₃ = 150, find Ar of R → 96
Chemistry Paper 1 Foundation 20222Mr of H₂CO₃ → 62
Combined Science Chemistry Paper 1 Foundation 20232Mr of H₂SO₄ → 98
Chemistry Paper 1 Foundation 20232Mr of Fe₂O₃ → 160
Chemistry Paper 2 Higher 20232Reverse: amino acid section from Mr = 75 → 14
Combined Science Chemistry Paper 2 Foundation 20242Mr of CO₂ → 44

The pattern: a near-annual 2-marker, mostly Foundation, mostly Paper 1 — one mark for the substitution, one for the answer. Higher tier sees it hidden inside bigger calculations instead, which is exactly why it's worth making automatic: get Mr wrong at step one of a 5-marker and every number after it is wrong too.

Now practise it — free

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More AQA GCSE Chemistry calculations

Conservation of massPercentage by massMoles ⇄ massReacting massesPercentage yieldAtom economyConcentration (g/dm³)Concentration (mol/dm³)